2x-8=2x^2-6x

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Solution for 2x-8=2x^2-6x equation:



2x-8=2x^2-6x
We move all terms to the left:
2x-8-(2x^2-6x)=0
We get rid of parentheses
-2x^2+2x+6x-8=0
We add all the numbers together, and all the variables
-2x^2+8x-8=0
a = -2; b = 8; c = -8;
Δ = b2-4ac
Δ = 82-4·(-2)·(-8)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-8}{-4}=+2$

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